Question

11. The quadratic polynomial whose zeroes are -3/2 and -5/3 is *

Answer 1

Answer:

Let the quadratic polynomial be: ax^2+bx+c

Put x=-3, 9a-3b+c=0

Put x =2, 4a+2b+c=0

Subtracting the equation: 5a-5b=0, i.e. a=b

Put back a = b in any of the above;

6a+c=0 => c=-6a

Therefore, our equation is: ax^2+ax-6a=0

So, for the required polynomial, replace with some non zero constant (like a=1)

Then You are done!

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Step-by-step explanation:

Answer 2

Answer:

x2 + 19x/60 + 5/2

Step-by-step explanation:

(x+3/2) (x+5/3)

= 1/6 (2x+3) (3x+5)

= x2 + 19x/60 + 5/2