Question

(11)The sum of the ages of father and son is 50. Five year later, age of the father will be twice age of
the son. Find their present age.​

Answer 1

Answer:

We have sum of present ages father and son as a+b=50, the age of father becomes thrice the age of son after 5 years,

a+5=3(b+5). Solving two equations

a+b=50 and a−3b=10 we get b=10 and a=40.

The present age of father is 40 years and of son is 10 years.

Answer 2

Answer:

father's age = 35

son's age = 15

Step-by-step explanation:

We have sum of present ages father and son as a = a +b=50. ____(i)

the age of father becomes twice of the age of son after 5 years.

a+5 = 2 (b+5)

a +5 = 2b +10

a = 2b + 10-5

a = 2b +5. ____ (ii)

substituting (I) and (ii)

(2b+5) + b = 50

2b+b = 50-5

3b = 45

b = 45/3

b = 15

so , b = 15 then,

15 + a = 50. (from (i) )

a = 50 - 15

a = 35