Question

11. Two resistance are joined in parelel
whose resultant
is 6/8 ohm. One of the resistance wires is broken
& the effective resistance becomes 2 ohm.Then
the resistance in ohm of the wire that got
broken
was -​

Answer 1

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Answer 2

$\blue{ \: hyy \: dude \: here \: is \: your \: answer}$

●》Let the resistance of the broken wire be x
ohm

resultant resistance when both the wires
were connected in parallel = 6/8 ohm

when one where is being disconnected,
the effective resistance = 2ohm

this is equal to the resistance of other wire

$\red \bigstar \red { \: in \: parallel \: combinrion}$
$\blue{ \: resultant \: resistance \:} \\ \\ \blue{ \: ( \frac{1}{r} ) \: = \: \frac{1}{r1} \: +\: \frac{1}{r2} \: }$

$\blue{ \: r \: = \frac{ \: r1 \: \times \: r2}{ \: r1 \: + \: r2 \: }}$

$\red{ \: here \: }$
$\blue{ \: r \: = \: \frac{6}{8} \: ohm} \\ \blue{ \: r1 \: = x \: ohm} \\ \blue{ \: r2 \: = \: 2 \: ohm}$

$\blue{ \: r \: = \frac{x \: \times \: 2}{x \: + \: 2 \: } = \frac{6}{8} \: ohm}$

$\blue{ \: 16 \: x \: = \: 6 \: ( \: x \: + \: 2 \: )}$

$\blue{ \: 8 \: x \: = \: 3x \: + \: 6 \: }$

5x = 6
x = 6/ 5 ohm
resistance of other wire is 6/ 5 ohm