Question

11. Two resistances of 10 and 20 02 and an
ideal inductor of inductance 5 H are connected
to a 2V battery through a key, as shown in the
figure. The key is inserted at t0. What is the
final value of current in the 10 resistor?
​

Answer 1

Answer:

use i=v/r

2/10

5

answer is 5 amp