Question

11 Two tables were sold at 990 each, one at a profit of 10% and the other at loss of 10%. What are the cost prices of each of the tables? In this sale, did the seller make a profit or loss? What is the percentage
of profit or loss?​

Answer 1

Answer:

S.p of each table =Rs 990

C.P of first table = 100/100+10×990

= 100/110×990

=900

C.p of sec.table = 100/100-10×990

= 100/90 ×990

= Rs 1100

Total s.p = 990+990=1980

Total c.p = 900+1100=2000

Here c.p>s.p

Loss =c.p-s.p =2000-1980

=20

Loss% =loss/c.p×100=20/2000×100

=1%

Answer 2

Step-by-step explanation:

Let original price of table sold at 10% profit = x

110% of X = 990

110/100 × X = 990

11/10 × X = 990

x = 990 × 10/11

x = 9900/11

= 900

Original Price of the table sold at 10% = 900

but

the selling price was 990 = 990-900 = Rs. 90 (Profit)

Total Price of two tables = 990 + 990 = 1980

Original price of other table = 1980-900 = 1080

But selling price was 990 = 1080-990 = 90 (loss)

Profit - loss = 90-90 = 0

Therefore seller broke even.

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