11. What is the conductivity of semiconductor if electron density= 5x1012/cm3 and hole
density = 8x1013/cm3 [μe=2.3 and μh=0.01 in SI units ]
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1
Answer:
Electron density =n
e
=5×10
12
/cm
3
=5×10
18
/m
3
Hole density =n
h
=8×10
13
/cm
3
=8×10
19
/m
3
The conductivity of the semiconductor
=e(μ
e
n
e
+μ
h
n
h
)
=1.6×10
−19
((2.3)(5×10
18
)+(0.01)(8×10
19
))
=1.968
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