Question

11. What is the conductivity of semiconductor if electron density= 5x1012/cm3 and hole

density = 8x1013/cm3 [μe=2.3 and μh=0.01 in SI units ]​

Answer 1

Answer:

Electron density =n

e

=5×10

12

/cm

3

=5×10

18

/m

3

Hole density =n

h

=8×10

13

/cm

3

=8×10

19

/m

3

The conductivity of the semiconductor

=e(μ

e

n

e

+μ

h

n

h

)

=1.6×10

−19

((2.3)(5×10

18

)+(0.01)(8×10

19

))

=1.968