A ball is gently dropped from a height of 20m if its velocity increases uniformly at the rate of 10 metre per second square with what velocity will it strike the ground? After what time will it strike the ground?
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- Initial velocity, (u) = 0
- Final velocity, (v) = ?
- Acceleration, (a) = 10 m/s²
- Distance, (s) = 20m
- Velocity at which the ball strike the ground.
- Time it will take to strike the ground.
- v² = u² + 2as
- v = u + at
As we know that;
Putting values in this formula,
We get;
v² = u² + 2as
v² = (0)²+2×10×20
v² = 0+400
v² = 400
v = √400
v = 20 m/s
As we know that;
Putting values in this formula,
We get;
v = u + at
20 = 0+10×t
10t = 20
t = 20/10
t = 2 sec
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