Question

11. What will be the volume of 2.8 g of carbon
monoxide at 27°C and 0.821 atmospheric
pressure?
(a) 2.5 L
(b) 4L (c) 3.5 L (d) 3 L​

Answer 1

Answer:

The volume of carbon monoxide=PnRT

Mass of carbon\quad monoxide=2.8g

P=0.821 atm,

T=27+273=300K

R=0.0821

because gram molecular weight of CO=12+16=28

because number of moles in 2.8g of CO=282.8=0.1

therefore volume=0.8210.1×0.0821×300=3 litre