Question

11. When a certain metal was irradiated with light of frequency 4 x 10 st. The phe
emitted had three times the kinetic energy as the kinetic energy of photoelen
when the metal was irradiated with light of frequency 2 x 100 s Calculate
frequency (vo) of the metal.
​

Answer 1

Answer:

KE1=h(V1−V0)------(i)

KE2=h(V2−V0)=

KE1

2

 

------(i)

Dividing equations (ii) by (i) we have

∴

V2−V0

V1−V0

 

=

1

2

 

1.0×1016−V0

1.6×1016−V0

 

=

1

2

 

2.0×1016−2V0=1.6×1016−V0

V0=4×1015Hz

Hence (c) is the correct answer