Question

11(x-5)+10(y-2)+54=0,7(2x-1)+9(3y-1)=25 by substitution method
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Answer 1

Answer:

Step-by-step explanation:

11(x-5) + 10(y-2) + 54 = 0

11x - 10y - 21 = 0

11x + 10y = 21............ (1)

7(2x-1) + 9(3y-1) = 25

14x - 7 + 27y - 9 = 25

14x + 27y -16 = 25

14x + 27y = 41............(2)

Multiplying equation (1) by 27 and equation (2) by 10 we get

297x + 270y = 567..............(3)

140x + 270y = 410...............(4)

Subtracting equation (4) from equation (3) we get

157x = 157

x = 1

Substituting x = 1 in equation (1) we get

11 × 1 + 10y = 21

10y = 10

y = 1

x = 1 and y = 1

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