111)
cosec (90° – 0).sin(180° — O) cot(360° – 6)
sec(180° +0) tan (90° +O) sin(-0)
= prove that
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Answer:
L.H.S.=
cos(90∘+θ)sec(-θ)tan(180∘-θ)
sec(360∘-θ)sin(180∘+θ)cot(90∘-θ)
= (-sinθ)secθ(-tanθ)
secθ(-sinθ)tanθ
=-1=R.H.S.
Explanation:
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