I need the answer of iv
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Step-by-step explanation:
eq¹:-(2)(3x+4y=10)
eq²:-(3)(2x-2y=2)
_______________
6x+8y=20
(—) 6x-6y=6
_______________
14y=14
y=1. .........(i)
put the value of y in eq¹
3x+4y=10
3x+4=10
3x=6
x=2
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