Question

I need the answer of iv
​

Answer 1

Step-by-step explanation:

eq¹:-(2)(3x+4y=10)

eq²:-(3)(2x-2y=2)

_______________

6x+8y=20

(—) 6x-6y=6

_______________

14y=14

y=1. .........(i)

put the value of y in eq¹

3x+4y=10

3x+4=10

3x=6

x=2