Question

111³-89³, what will be the answer. answer correct only

Answer 1

Explanation:

$\Huge\red{\mathfrak{ Answer }}$

Using the identity a^3-b^3= (a-b) (a^2+ab+b^2)

we have

111^3-89^3

= (111-89)(111^2+111*89*89^2)

=22(12321+9879+7921)

= 22(30121)

= 662662

hope it helps ✌

Answer 2

Answer:

identity -

a³-b³ = (a-b)(a²+b²+ab)

111³ -89³

= (111-89) {(111)² +(89)² +(111 × 89)}

identity =

(a+b)² = a²+b²+2ab

(111)² = (100+11)²

= {(100)²+(11)²+2(100×11)}

= (10000+121+2200)

= 12321

(89)²

= (90-1)²

identity-

(a-b)² = a²+b²-2ab

{(90)²+(1)²-2(90×1)}

= (8100+1-180)

= 7921

(111 ×89)

111 = 100+11

89= 100-11

(100+11)(100-11)

identity -

(a+b)(a-b) = a²-b2

= (100)²-(11)²

= 10000-121

= 9879

by putting the values

(111-89)(12321+7921+9879)

= 22 × 30121

= .662662(answer)