Question

115÷5+12*6=x + 64÷4-35
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Answer 1

Step-by-step explanation:

$\frac{115}{5} + 12 \times 6 = x + \frac{64}{4} - 35$

$23 + 72 = x + \frac{64 - 130}{4}$

$x = 100 + \frac{66}{4}$

$x = \frac{400 + 66}{4}$

$x = \frac{466}{4}$

$x = \frac{233}{2}$

$x = 116.5$

Answer 2

Answer:

Required value of x is 114.

Step-by-step explanation:

Given,115÷5+12*6=x + 64÷4-35

By BODMAS rule,we can solve this.

By BODMAS rule,

Bracket - Of - Division - Multiplication - Addition - Subtraction

So,

$115 \div 5 + 12\times 6 = x + 64 \div 4 - 35 \\ \frac{115}{5} + 12 \times 6 = x + \frac{64}{4} - 35 \\ 23 + 12 \times 6 = x + 16 - 35 \\ 23 + 72 = x - 19 \\ x = 23 + 72 + 19 \\ x = 114$

Therefore required value of x is 114.

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

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