116 को चार भागो मे बाटा गया पहले भाग मे 5 जोड़ने पर दूसरे भाग मे 4 घटाने पर तीसरे भाग मे 3 से गुना करने पर चोथे भाग मे 2 से भाग देने पर संख्या समान हो
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what is the question
please ask in detail
please ask in detail
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let the 4 no. be x, y, w and z respectively
x + y + w + z = 116
x + 5 = y - 4 = 3w = z / 2 ......(1)
from (1)
x = y - 9. .....(2)
w =( y - 4)/ 3. ......(3)
z = 2y - 8. .......(4)
using (2) , (3) & (4)
(y - 9 ) + (y) + { (y-4) / 3 } +(2y- 8) = 116
→ 13y - 55 =348
→ 13y = 403
→ y = 31
on putting the value of y in equ. (2) , (3) & (4)
respectively ---
x = 22
w = 9
z = 54
the 4 no are 22, 31, 9 and 54
22 + 31 + 9 + 54 = 116
22+5 = 31 - 4 = 3 × 9 = 54÷2 = 27
hence the ans is 22, 31, 9 ,54
x + y + w + z = 116
x + 5 = y - 4 = 3w = z / 2 ......(1)
from (1)
x = y - 9. .....(2)
w =( y - 4)/ 3. ......(3)
z = 2y - 8. .......(4)
using (2) , (3) & (4)
(y - 9 ) + (y) + { (y-4) / 3 } +(2y- 8) = 116
→ 13y - 55 =348
→ 13y = 403
→ y = 31
on putting the value of y in equ. (2) , (3) & (4)
respectively ---
x = 22
w = 9
z = 54
the 4 no are 22, 31, 9 and 54
22 + 31 + 9 + 54 = 116
22+5 = 31 - 4 = 3 × 9 = 54÷2 = 27
hence the ans is 22, 31, 9 ,54
dheerajgour:
thanks
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