Question

116 को चार भागो मे बाटा गया पहले भाग मे 5 जोड़ने पर दूसरे भाग मे 4 घटाने पर तीसरे भाग मे 3 से गुना करने पर चोथे भाग मे 2 से भाग देने पर संख्या समान हो

Answer 1

what is the question
please ask in detail

Answer 2

let the 4 no. be x, y, w and z respectively

x + y + w + z = 116


x + 5 = y - 4 = 3w = z / 2 ......(1)

from (1)

x = y - 9. .....(2)

w =( y - 4)/ 3. ......(3)

z = 2y - 8. .......(4)

using (2) , (3) & (4)

(y - 9 ) + (y) + { (y-4) / 3 } +(2y- 8) = 116

→ 13y - 55 =348

→ 13y = 403

→ y = 31

on putting the value of y in equ. (2) , (3) & (4)
respectively ---

x = 22

w = 9

z = 54

the 4 no are 22, 31, 9 and 54

22 + 31 + 9 + 54 = 116

22+5 = 31 - 4 = 3 × 9 = 54÷2 = 27

hence the ans is 22, 31, 9 ,54