solve the given question
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1+tan30/1-tan30
Since tan 30=1/√3
1+1/√3/1-1/√3
√3+1/√3/√3-1/√3
√3 get cancelled
So √3+1/√3-1
Rationalizing so multiplying by √3+1 for both numerator n denominator
(√3+1)^2/(√3-1)^2
4+2√3/2
4/2+2√3/2
i.e,2+√3
Hence proved
LHS=RHS
Since tan 30=1/√3
1+1/√3/1-1/√3
√3+1/√3/√3-1/√3
√3 get cancelled
So √3+1/√3-1
Rationalizing so multiplying by √3+1 for both numerator n denominator
(√3+1)^2/(√3-1)^2
4+2√3/2
4/2+2√3/2
i.e,2+√3
Hence proved
LHS=RHS
Haeshu2002:
Can u get it..?
from last 3 step not understand
Denominator is common for two term that is 4 and 2√3...so take it seperately n solve
can u solve my net question
can u solve my next question
the question is to find magnitude
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