Question

116 mg of a compound vaporization in victor meyer's apparatus displaces 44.8 ml of air of air measured at stp. The molecular weight of the compound is

Answer 1

given, 116 mg of a compound vaporization in victor meyer's apparatus displaces 44.8 ml of air of air measured at stp.

given volume = 44.8ml

so, number of mole of compound = given Volume/22400 ml

= 44.8ml/22400ml

= 2/1000 = 0.002

we know, no of moles of compound = given weight/molecular weight of compound

so, 0.002 = 116mg/molecular weight of compound

is, molecular weight of compound = 116 × 10^-3 g/0.002

= 58g/mol

hence, molecular weight of compound is 58g/mol

Answer 2

Answer:

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