Math, asked by harsh5797, 9 months ago

118. The equation of the straight line passing
through the points (-5, 2) and (6,-4) is :

Answers

Answered by sathish24499k
3

(y-y1)/(y2-y1)=(x-x1)/(x2-x1)

X1=-5

X2=6

Y1=2

Y2=-4

(y-2)/-6 =(x+5)/1

Y-2=(-6)(x+5)

Y-2=-6x-30

6x+y+28=0

Answered by Rosni12345
57

Answer:

(Y y1) /(2 y1)=(x–x1/(×2×1)

X1=5

X2=6

Y1=2

Y2=4

(y-2)/-6=(x+5)/1

Y-2=(-6)(×+5)

Y-2=6×-30

6×+y+28=0

Step-by-step explanation:

Please mark me brainliest .please please please please please brother please.

Similar questions