11a(cube)b(cube)(7c-35)÷3a(square)b(square)(c-5)
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we have ,

Putting 7(c-5) in place of (7c - 35) and dividing a³b³ by a²b², we get,

Regards
KSHITIJ
Putting 7(c-5) in place of (7c - 35) and dividing a³b³ by a²b², we get,
Regards
KSHITIJ
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