Question

(-11t-55/122)=(38t+34/112)​

Answer 1

Answer:

$(\frac{-11t-55}{122})=(\frac{38t+34}{112})\\\\112(-11t-55)=(38t+34)122\\\\-1232t-67760=4636t+4148\\\\-1232t-4636t=4148+67760\\\\-5868t=71908\\\\t=\frac{-71908}{5868}$

I hope this helps........