12, 1, 1), D (3,3,-1), then b =
(a) 1
(b) 2
le) 3
(d) 4
2) Given P = (3. - 6, 10) and PQ = V17. If direction
-2.
3
-2.
cosines of line PQ are T 717 777
5
then point
can be
(a) (5, 12, -9)
(c) (-9,5, 12)
(b) (1, -3,8)
(d) (-2,3,-2)
nes of a line .
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Answer:
option b in first part and c in second part and d in third part please mark me the brainlyiest
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