Question

(1²-2²+3²-4²+5²-6²+....+9²-10²) = ?

Answer 1

$\red{The \: value \: of \: (1^{2}-2^{2}+3^{2}-4^{2}+\ldots+9^{2}-10^{2})}$

$= (1^{2} - 2^{2})$

$+ (3^{2} - 4^{2})$

$+(5^{2} - 6^{2})$

$+ \ldots -$

$+(9^{2} - 10^{2})$

$= (1+2)(1-2)$

$+ (3+4)(3-4)$

$+ (5+6)(5-6)$

$+ (7+8)(7-8)$

$+ (9+10)(9-10)$

$= 3\times (-1)+ 7\times (-1)+ 11\times (-1)+ 15\times (-1)+ 19\times (-1)$

$= -( 3+7+11+15+19)$

$= -55$

Therefore.,

$\red{The \: value \: of \: (1^{2}-2^{2}+3^{2}-4^{2}+\ldots+9^{2}-10^{2})}$

$\green{ = -55}$

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Answer 2

Answer:

bro the given answer is correct

but can u say me how to write answers in colourful way