Question

12.
2x - 3y + 6 = 0
2x + 3y - 18 = 0 simulataneous equation​

Answer 1

Answer:

After solving the given equation, we get x=3 and y=4.

Step-by-step explanation:

Given: $2x - 3y + 6 = 0,2x + 3y - 18 = 0$

We have to solve the above simultaneous equation.

We are solving in the following way:

We have,

$2x - 3y + 6 = 0,2x + 3y - 18 = 0$

Solving for x:

$\begin{array}{l}2 x-3 y+6=0 \\\\\Rightarrow 2 x=3 y-6 \\\\\Rightarrow x=\frac{3 y-6}{2}\ \ \ ...(1)\end{array}$

And

$2x + 3y - 18 = 0$

Solving for y:

$\begin{array}{l}2 x+3 y-18=0 \\\\\Rightarrow 2\left(\frac{3 y-6}{2}\right)+3 y=18 \ \ \ ..from(1)\\\\\Rightarrow 3 y-6+3 y=18 \\\\\Rightarrow 6 y=24 \\\\\Rightarrow y=4\end{array}$

Substituting the value of y in (1), we have

$x=\frac{3 \times 4-6}{2}\\\\=\frac{12-6}{2}\\\\=\frac{6}{2\\}\\\\=3$

Therefore, the solution is x=3 and y=4.