12. 4(a + b)- 6 (a + b)2
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1
Answer:
Answer
Since in the expression 4(a+b)
2
−6(a+b), 2(a+b) is the common term, therefore, can be factorised as follows:
4(a+b)
2
−6(a+b)=2(a+b)[2(a+b)−3]
samikshaaalikal:
could u pls explain how did u get the final answer
Answered by
1
Answer:
4a + 4b - 12a - 12b
-8a - 8b
-8(a + b)
can you resend the question
yaaa just a sec
4(a + b)- 6 (a + b)2
is that a square
yesss
of (a+b)^2 that's what you mean
yaa right
ohk
that's why I didn't get that
4a+4b -6(a2 +2ab+b2) = 4a +4b-6a2-6ab-6b2 = 2(2a+2b-3a2-3ab-3b2) = 2[a(2-3b-3a)+b(2-3b)]
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