Question

A circular coil of conducting

wire has 500 turns and an area 1.26×10-4 m2is enclosed by the coil. A current 100 µA is passed through the coil. Calculate the

magnetic moment of the coil.​

Answer 1

Solution:

µ = NIA

= 500 × 100 × 10-6 × 1.26 × 10-4 Am2

= 630 × 10-8 = 6.3 × 10-6 Am2 or J/T.

Answer 2

The magnetic moment of the coil is 6.3 × 10⁻⁶ Am².

A circular coil of conducting wire has 500 turns and an area 1.26 × 10⁻⁴ m² is enclosed by the coil. A current 100μA is passed through the coil.

We have to calculate the magnetic moment of the coil.

Magnetic moment :

• magnetic moment or magnetic dipole moment is a vector quantity. It is tendency of an object to align with a magnetic field.
• It is the product of current flowing through it and the cross sectional area of it. i.e., M = IA
• For a coil, number of turn is N, then magnetic moment of coil, M = ANI

Here number of turns , N = 500

cross sectional area, A = 1.26 × 10⁻⁴ m²

current flowing through the coil, I = 100μA = 10⁻⁴A

∴ magnetic moment, M = ANI

= 10⁻⁴ × 500 × 1.26 × 10⁻⁴

= 6.3 × 10⁻⁶ Am²

Therefore the magnetic moment of the coil is 6.3 × 10⁻⁶ Am².

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