Question

12. A ball is dropped from the top of a high rower.
Distance travelled by the ball in 2nd second of its
motion is (g= 10 m/s]​

Answer 1

Answer:

20meters is the distance travelled in 2sec

Answer 2

Answer:

15 metres

Explanation:

According to the formula,

$distance \: travelled \: in \: the \: \: {n}^{th} \: second = u + a(n - \frac{1}{2} )$

Since ball is dropped from top of tower,

Initial velocity, u = 0

Acceleration, a = 10 m/s^2

Second, n = 2

By substituting values,

$distance \: travelled \: in \: {2}^{nd} \: second = 0 + 10(2 - \frac{1}{2} ) \\ = 0 + 10( \frac{4 - 1}{2} ) \\ = 10 \times \frac{3}{2} \\ = 5 \times 3 = 15 \: m$

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