Question

12. A body moving with a constant acceleration
( travels the distances 3 m and 8 m respectively in 1
s and 2 s. Calculate : (i) the initial velocity, and (ii)
the acceleration of body.​

Answer 1

Explanation:

• since, a=constant
• s1= 3 metre and t1=1 sec
• s2= 8 metre and t2= 2s

We know that,

Snth= u+a/2(2n-1)

so, s1=u+a/2(2n-1)

3=u+a/2(2 X 1-1)

3=u+a/2 ------------(i)

again, s2=u+a/2(2n-1)

8= u+a/2(2 X 2-1)

8= u+a/2 X 3

8= u+3a/2-------------(ii)

From (i) and (ii)-----

solving both equations,

8=4a/2

8=2a

====> a=4 m/s^2(acceleration)

Putting value of "a" in eq. 1---

3=u + 4/2

3=u + 2

u= 1 m/s===>initial velocity

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