Question

12. A Box contains 3 red balls, 7 black balls and 5 green balls. One ball is drawn from the box at
random. Find the probability of drawing a) a green ball b) a black ball c) a red ball.​

Answer 1

Number of red balls = 3

Number of black balls = 7

Number of green balls = 5

Total number of balls = 3 + 7 + 5 = 15

(a) Probability of drawing green ball =

$= \frac{5}{15} = \frac{1}{3}$

(b) Probability of drawing black ball =

$= \frac{7}{15}$

(c) Probability of drawing red ball =

$= \frac{3}{15} = \frac{1}{5}$

Answer 2

Answer:

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Step-by-step explanation:

Number of red balls = 3

Number of black balls = 7

Number of Green balls = 5

Total number is balls = 3 + 7 + 5 = 15

Probability = Favourable Events / Total Events

a) a green ball = 3/15 = 1/5

b) a black ball = 7/15

c) a red ball = 5/15 = 1/5