Question

12. A cylindrical tube which is 28 cm long is made
of iron. If its internal radius is 6 cm and is 0.5 cm
thick and open at both ends, calculate the
volume of iron.
​

Answer 1

Answer:

550cm³

Step-by-step explanation:

h=28

R1 =6

R2=6.5

volume=π (R2²— R1² ) h

=22/7 ( 6.5²—6²) 28

=550cm³

Answer 2

Answer:

550 cm^3

Step-by-step explanation:

given : Internal radius (r) = 6cm

Length of the tube (h) = 28cm

thickness of cylinder = 0.5 cm

Volume of internal cylinder =πr^2h

=22/7*6*6*28

= 22*6*6*4

= 3168 cm^3

External radius = R=(6+0.5)= 6.5

Volume of external cylinder = πR^2h

=22/7*6.5*6.5*28

=22*6.5*6.5*4

=3718 cm^3

volume of iron = volume of external cylinder - volume of internal diameter

= (3718 - 3168) cm^3

= 550 cm^3