Math, asked by alok763390, 8 months ago

12. A largest number of three digits when
divided by 2, 5, 9, 11 leaves remainder 1 in
each case. The number is
(a) 981
(b) 983
(c) 991
(d) 997


plz it's urgent solve it if who one will solve it I will mark him as brainlist answer​

Answers

Answered by rlakhanparsad
2

Answer:

Last - x-1= 990

x= 990+1

x= 991

you can also solve like 2 nd image

Attachments:
Answered by Tombiju14
3
981
Pls mark me as brain lies
Similar questions