Question

12. A mass of 10 kg is dropped from a height of 50 cm. Find its :
(a) potential energy just before dropping
(b) kinetic energy just before touching the ground
(el velocity with which it hits the ground (Given g = 10 ms )

Answer 1

Answer:

Explanation:

P.E before dropping = m x g x h

10 x 10 x 50 = 5000

K.E on touching the ground = 0

because, k.e = 1/2 x m x v²

on touching ground, v = 0

So, 1/2 x 10 x 0 = 0

,

Vel = 10 m/s

Answer 2

Answer:

(a) m= 10kg

g=10ms-2

h= 50cm=0.05m

Potential energy= mgh

= 10x10x0.05

= 5J