Math, asked by praveen1510, 1 year ago

f(x)= 4√2/3*x^1/2
f'(x) = ?

Answers

Answered by ranjankumartc

1

Answer:

Step-by-step explanation:f(x)= {4√(2/3)}x^1/2

f'(x)= {4√(2/3)}×1/2×x^(1/2-1)

={2√(2/3)}×(1/√x)

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