Question

12. A metro rail is full of passengers when it starts from station A. At station B it drops 50 passengers, which is more than half of its total passengers and takes one-third of full capacity more. At station C, it takes 60 more passengers and drops two-thirds of passengers at the next station D. After reaching station E, the train drops all the 70 passengers left in the train. What was the number of passengers in the train when it left from station B?
a. 240
b. 150
c. 210
d. 160

Answer 1

this is your answer

egg and the other day and

Answer 2

150 passengers in the train when it left from station B.

Step-by-step explanation:

A metro rail is full of passengers from station A.

Let the number of passengers at station A = x

At station B it drops 50 passengers and takes $\frac{1}{3}$ of x

=  $x-50+\frac{1}{3}x$

=  $\frac{3x+x-150}{3}$

= $\frac{4x-150}{3}$

At station C it takes 60 more passengers.

= $\frac{4x-150}{30}+60$

= $\frac{4x-150+180}{3}$

= $\frac{4x+30}{3}$

At station D it drops two-third of passengers.

= $\frac{4x+30}{3}-\frac{2}{3}(\frac{4x+30}{3})$

= $\frac{4x+30}{3}(1-\frac{2}{3})$

= $\frac{4x+30}{3}(\frac{1}{3} )$

= $\frac{4x+30}{9}$   [ number of passengers after dropping passengers at station D ]

Now at station E the train drops all the 70 passengers.

∴  $\frac{4x+30}{9}=70$

⇒ 4x = 630 - 30

⇒ $x=\frac{600}{4}$

⇒ x = 150

Now put the value of x to the passengers at station B.

$\frac{4(150)-150}{3}$

$=\frac{600-150}{3}$

$=\frac{450}{3}$

= 150

Option B. 150 passengers.

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