12. A partide moves thought a distance
a distance of sm doe east
and then um due north. How much is the not
distance traversed!
1)3m 2)7m 3)8m 4)10m
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According to the question,,
BC = 6cm
AB = 8cm
To find : displacement of particle
Since displacement is the shortest path travelled by the body then we have to find AC.
AC^2 = AB^2 + BC^2 ( by pythagoras therom)
AC^2 = 8^2 + 6^2
AC^2 = 64 + 36
AC^2 = 100
AC = root 100
AC = 10cm
So, the displacement of the particle is 10 cm .
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