Question

12. a x2 + (ax? + 1) x + a

urgent​

Answer 1

Answer:

ok ok i give you ans

please follow me

Answer 2

Answer:

Given equations, x2+ax+1=0

x2−x−a=0

∵b is common root, so b satisfied both equations.

b2+ab+1=b2−b−a

=ab+b=−a−1

⇒b(a+1)=−(a+1)

⇒b=−1