Question

12. An object is placed at a distance of 10 cm from a convex mirror of focal length
15 cm. Find the position and nature of the image.
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Answer 1

Answer:

$\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$

$\frac{1}{v} = \frac{1}{f} + \frac{1}{u}$

Answer 2

Answer:

+ 6 cm

Explanation:

Given :

Object distance = - 10 cm

Focal length = + 15 cm

We have to find image distance.

We know :

1 / f = 1 / v + 1 / u

1 / v = 1 / f - 1 / u

1 / v = 1 / 15 + 1 / 10

1 / v = 1 / 6

v = + 6 cm

Hence .image distance is 6 cm from the mirror behind it.

The image is erect and virtual.