Question

12. Calculate the resistance in the following combination of resistors.
​

Answer 1

Explanation:

5 ohm

please mark my answer in brainlist

Answer 2

Answer:

In this case, the first two resistors of 2 ohms each are connected in series and the third and fourth resistors of 2 ohms each are connected in parallel. The first set is connected in series with the second set of resistors.

The resistances R3 and R4 that are connected in parallel have a resistance given as

2 1 + 2 1= 11 =1o hm

That is, these two resistances is reduced to a single resistance of 1 ohm.

The resistances R1 and R2 that are connected in series have a resistance given as 2+2 = 4 ohms.

This combined resistance when connected in series with reduced resistance of 1 ohm gives a total resistance of 4+1 = 5 ohms.

Hence, the total resistance in the circuit is 5 ohms.