Question

12)Can 5cm, 12cm and 13cm be sides of a night angled in 13) In the figure given below. Show that ABD =ACD. A 3.5 cm 3.5 cm D 2.5 cm C B 2.5 cm​

Answer 1

Answer:

In right angles triangle BAC, AB=5cm and AC=12cm

Area of triangle=

2

1

×base×height=

2

1

×AB×AC

=

2

1

×5×12=30cm

2

Now, in ΔABC,

Area of triangle ABC=

2

1

×BC×AD

⇒30=

2

1

×13×AD

⇒ AD=

13

30×2

=

13

60

cm.

Answer 2

write in proper way

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Step-by-step explanation:

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