Question

in a certain code language Easy is written as 5117 .In the same code language how will BEAM be written as?​

Answer 1

Answer:

EASY → E is the 5th alphabet in the series

A is the first alphabet in the series

S is the 19th alphabet, which makes it (1+9 = 10 ⇒ 1+0 = 1)

Y is the 25th alphabet, which makes it (2+5 = 7)

Hence, EASY = 5117

Similarly,

BEAM → B is the 2nd alphabet in the series

E is the 5th alphabet in the series

A is the 1st alphabet in the series

M is the 13th alphabet, which makes it (1+3 = 4)

Hence BEAM = 2514

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Answer 2

The fifth alphabet in the series is EASY E.

The letter A is the first in the sequence.

S is the 19th letter of the alphabet (1+9 = 10 1+0 = 1)

Y is the twenty-fifth alphabet, making it (2+5 = 7)

As a result, EASY = 5117.

Similarly,

The second alphabet in the series is BEAM.

The fifth alphabet in the series is E.

The first alphabet in the series is A.

M is the thirteenth alphabet, making it (1+3 = 4)

As a result, BEAM = 2514.