A car moves from one end of a semicircular path of radius r, to the other end. For this car, ratio of pathlength to the magnitude of the displacement will be ................ .
(A) Ï/2
(B) Ï
(C) 3Ï/2
(D) 2Ï
Answers
Answered by
20
Answer:
π/2
Explanation:
semicircular path of radius r
Circumference of Semicircle = πr
Path Length = πr
Displacement between two ends of a semicircle = Diameter of circle
= 2 * radius
= 2r
ratio of pathlength to the magnitude of the displacement will be = πr/2r
= π/2
Answered by
5
Answer:
option A : π/2
Explanation:
we know that length of path is distance covered and displacement is the shortest path between source and destination.
circumference of circle= 2πr
circumference of half circle[ semicircle)= πr
diameter = r [ according to question ]
radius = diameter/2=r/2
ratio of length of path/ magnitude of displacement =πr/2/r=π/2
∴ratio of path length to the magnitude of the displacement will be=π/2
Attachments:
Similar questions
Chemistry,
6 months ago
Social Sciences,
6 months ago
Environmental Sciences,
6 months ago
Physics,
1 year ago
Physics,
1 year ago
Social Sciences,
1 year ago