Physics, asked by liza9641, 1 year ago

A car moves from one end of a semicircular path of radius r, to the other end. For this car, ratio of pathlength to the magnitude of the displacement will be ................ .
(A) Ï/2
(B) Ï
(C) 3Ï/2
(D) 2Ï

Answers

Answered by amitnrw
20

Answer:

π/2

Explanation:

semicircular path of radius r

Circumference of Semicircle = πr

Path Length  = πr

Displacement between two ends of a semicircle = Diameter of circle

= 2 * radius

= 2r

ratio of pathlength to the magnitude of the displacement will be  = πr/2r

= π/2

Answered by prmkulk1978
5

Answer:

option A : π/2

Explanation:

we know that length of path is distance covered and displacement is the shortest path between source and destination.

circumference of circle= 2πr

circumference of half circle[ semicircle)= πr

diameter = r [ according to question ]

radius = diameter/2=r/2

ratio of length of path/ magnitude of displacement =πr/2/r=π/2

∴ratio of path length to the magnitude of the displacement will be=π/2

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