Question

The electric force between two electric charges is given by F = 1/4Ïεâ qâqâ/r², where r is the distance between qâ and qâ. Give the unit and dimensional formula of εâ.

Answer 1

Answer:

$[ML^3T^{-4}A^{-2}]}$

Explanation:

The force between charges is given by

$F=\frac{1}{4}\mu\frac{q_1q_2}{r^2}$

or

$\mu=\frac{4Fr^2}{q_1q_2}$

Dimensions of F = $[MLT^{-2}]$

Dimensions of r = $[L^2]$

Dimensions of q = $[AT]$

Therefore,

Dimensions of μ

$=\frac{[MLT^{-2}][L^2]}{[AT]^2}$

$=\frac{[ML^3T^{-2}]}{[A^2T^2]}$

$=[ML^3T^{-4}A^{-2}]}$

Hope the answer is helpful.