Question

12- Check the correctioness
i rat police
of following
v=rate of flow of liquid.
二月
Creffient of visocity
gradient 18=radi
Pl .= presure​

Answer 1

Answer:

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Answer 2

Answer:capillary viscometer

The the mathematical expression describing the flow of fluids in circular tubes was determined by the French physician and physiologist Jean Poiseuille (1799–1869). Since it was also discovered independently by the German hydraulic engineer Gotthilf Hagen (1797–1884), it should be properly known as the Hagen-Poiseuille equation, but it is usually just called Poiseuille's equation. I will not derive it here. (Please don't ask me to.) For non-turbulent, non-pulsatile fluid flow through a uniform straight pipe, the volume flow rate (qm) is…

directly proportional to the pressure difference (∆P) between the ends of the tube

inversely proportional to the length (ℓ) of the tube

inversely proportional to the viscosity (η) of the fluid

proportional to the fourth power of the radius (r4) of the tube

qm =  π∆Pr4

8ηℓ

Solve for viscosity if that's what you want to know.

η =  π∆Pr4

8qmℓ

capillary viscometer… keep writing…

falling sphere

The mathematical expression describing the viscous drag force on a sphere was determined by the 19th century British physicist George Stokes. I will not derive it here. (Once again, don't ask.)

R = 6πηrv

The formula for the buoyant force on a sphere is accredited to the Ancient Greek engineerArchimedes of Syracuse, but equations weren't invented back then.

B = ρfluidgVdisplaced

The formula for weight had to be invented by someone, but I don't know who.

W = mg = ρobjectgVobject

Let's combine all these things together for a sphere falling in a fluid. Weight goes down, buoyancy goes up, drag goes up. After a while, the sphere will fall with constant velocity. When it does, all these forces cancel. When a sphere is falling through a fluid it is completely submerged, so there is only one volume to talk about — the volume of a sphere. Let's work through this.

B  +  R  =  W  

ρfluidgV  +  6πηrv  =  ρobjectgV  

6πηrv  =  (ρobject − ρfluid)gV

6πηrv  =  ∆ρg  

4

3

πr3

And here we are.

η =  2∆ρgr2

9v

Explanation: