Question

12, Densities of two gases, neon and argon, are in the ratio 1 : 2 and their temperatures are in
the ratio 2 : 1. Then, the ratio of pressures of neon to that of argon is
(A) 1:1
(B) 1:2
(C) 2:1
(D) 4:1​

Answer 1

Answer:

Answer:(A) 1:1

Explanation:

The densities of two gases are in the ratio 1:2

and their temperature are in the ratio 2:1

Then the ratio of their respective pressure is 1:1.

PV= nRT= (W/M)RT

PM= (W/V)RT      

=dRTP/dT

= R/M= CONSTANT

P/dT= P'/d'T'

P/P'=dT/dT'

as we know,

d/d'=1/2

and T/T'=2/1

using these ratios

we can find the

P/P'= 1/2*2/1=1/1

Hence, option 1 follows.

#spj3​ ​

Answer 2

Concept introduction:

A material's density is defined as its weight or volume. Density is most frequently represented by the figure, however Latin letter $D$ may also be used. Density is expressed mathematically as mass dividing by volume.

Explanation:

We have to choose and find the correct option of the question.

A question has been given to us.

The densities of two gases are in the ratio $1:2$ and their temperature are in the ratio $2:1$

Then the ratio of their respective pressure is $1:1$

$PV= nRT= (W/M)RT$

$PM= (W/V)RT$ $=dRTP/dT$

$= R/M=$ CONSTANT

$P/dT= P'/d'T'$

$P/P'=dT/dT'$

as we know,

$d/d'=1/2$

and $T/T'=2/1$

using these ratios we can find the

$P/P'= 1/2*2/1=1/1$

Final answer:

So, the correct option of the question is option $(A) 1:1$.

#SPJ3