Question

12. Distance of the point whose ordinate is 3 and abscissa is 7 from the point (-1,4) is _______​

Answer 1

Answer:

Step-by-step explanation:

A(7,3), B(-1,4)

Distance AB =

$\sqrt{(-1-7)^{2} +(4-3)^{2} }$

=$\sqrt{(-8)^{2}+(1)^{2}  }$

=$\sqrt{64+1}$

=$\sqrt{65} units$