Math, asked by kolaakil98, 6 months ago

12. Find the area of the triangle
whose vertices are (0,0), (3, 0)
and (0,2) answer: step -1 ∆=1/2|x1(y2-y1)+x2 (y3-y1)+x3(y1-y2) | step-2 ∆=1/2|0(0-2)+3(2-0)+0(0-0)| =1/2|6|=3 square units 1/2|x1y2-x2y1|

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Answered by Anonymous

0

Answer:

answer is 3 square units

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