Question

12. Find two consecutive positive integers whose sum is 63.​

Answer 1

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$\huge{\underline{\underline{\sf{\blue{SOLUTION:-}}}}}$

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$\sf{\underline{\green{AnswEr:-}}}$

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• First number = 31
• Second number = 32

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$\sf{\underline{\green{Given:-}}}$

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• Two consecutive positive integers whose sum is 63.

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$\sf{\underline{\green{Find:-}}}$

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• First number = ?
• Second number = ?

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$\sf{\underline{\green{Explanation:-}}}$

Let the first number be y.

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• Second number = y + 1

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$\sf{\underline\pink{A.T.Q:-}}$

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$\longrightarrow \sf {y + y + 1 = 63}$

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$\longrightarrow \sf {2y + 1 = 63}$

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$\longrightarrow \sf {2y = 63 - 1}$

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$\longrightarrow \sf {2y = 62}$

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$\longrightarrow \sf {y = \cancel\dfrac{62}{2} }$

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$\longrightarrow \sf {y = 31}$

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$\:\:\:\:\dag\bf{\underline{\underline \red{Hence:-}}}$

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• First number = 31

• Second number = 31 + 1

• Second number = 32

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$\rule{200}{2}$

Answer 2

Answer:

Let first no. is =x

Second no. is=x+1

x + x+1=63

2x+1=63

2x=63-1

2x=62

x=31

Then the second value is x+1

So, 31+1=32

So, First positive integers is 31 and second is 32