Question

A number when multiple by 4 exceeds itself by 45

Answer 1

$\mathfrak{\large{\underline{\underline{Answer :-}}}}$

The Number is 15

$\mathfrak{\large{\underline{\underline{Explanation :-}}}}$

Given :

The number when is multiplied by 4 = exceeds itself by 45

To Find :

The Number

Solution :

Consider the Number as x

★ $\boxed{\sf{4 \times x =x+45}}$

$\longrightarrow$ 4 × x = x + 45

$\longrightarrow$ 4x = x + 45

$\longrightarrow$ 4x - x = 45

$\longrightarrow$ 3x = 45

$\longrightarrow$ x = 45/3

$\longrightarrow$ x = 15

$\therefore$ The Number is 15

$\rule{300}{1.5}$

$\mathfrak{\large{\underline{\underline{Verification :-}}}}$

$\longrightarrow$ 4 × 15 = 15 + 45

$\longrightarrow$ 60 = 60

$\therefore$ The Number is 15

Answer 2

Class - 7th  

$\mathfrak{\large{\underline{\underline{Answer:-}}}}$

The required number is 15.

$\mathfrak{\large{\underline{\underline{Explanation:-}}}}$

Given that :

A number when multiple by 4 exceeds itself by 45

4x = x + 45.

To Find :

The required number.

Solution :

Let the required number be "y"

$\sf \implies4x = y + 45\\\\\sf \implies4x-y = 45\\\\\sf \implies3y = 45\\\\\sf \implies y =  \dfrac{45}{3}\\\\\implies y = 15$

Hence, The number is 15.

_________________________________

$\mathfrak{\large{\underline{\underline{Verification:-}}}}$

$\sf \implies 4x =x+45\\ \sf \implies4\times15 =15+45\\ \sf \implies 60 =60$

Hence, The answer is Correct.