12. Find two consecutive positive integers whose sum is 63.
Answers
Answered by
1
Answer:
32 , 33
Step-by-step explanation:
Let the pos. integers be x and x+1
So x+x+1= 63
or 2x= 62
or x = 32
Thus first number is 32
and second is 33 (32+1)
Answered by
0
Step-by-step explanation:
Let, 1st number =x
2nd number =x+1 ( consecutive numbers)
Thus,
x+x+1=63
2x+1=63
2x=63−1
2x=62
x=262
x=31
x+1=31+1=32
∴ The required numbers are 31 and 32
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