12 g Me react with dilute mineral acid to pr.oduce maximum hydrogen equals to
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perhaps the metal is Mg
the reaction is
Mg + 2HCl =MgCl2 +H2
24 g. 2g or 22.4L at STP
12 g Mg gives H2 =2*12/24g=1g or
=22.4*12/24L=11.2L H2
the reaction is
Mg + 2HCl =MgCl2 +H2
24 g. 2g or 22.4L at STP
12 g Mg gives H2 =2*12/24g=1g or
=22.4*12/24L=11.2L H2
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