Math, asked by avinashdixit584, 1 month ago

12. Given set: (641, 507, 715)
(a) (371, 237, 823)
(b) (372,238, 824)
(c) (471, 328, 842)
(d) (237, 237, 823)
(e) (864, 928, 203)

Answers

Answered by harjot2641
0

Answer:

(c) (471, 328, 842)is answer of question

Answered by swaggy333333
0

Answer:

a.(371,237,823)

Step-by-step explanation:

641,507,715

=> 6+4+1=11

5+0+7=12

7+1+5=13

371,237,823

=> 3+7+1=11

2+3+7=12

8+2+3=13

all are in sum series of 11,12,13

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